Linux的path_alloc函数
发布时间:2016-11-18 08:35:29 所属栏目:Linux 来源:网络整理
导读:#include apue.h #include errno.h> #include limits.h> #ifdef PATH_MAX static int pathmax = PATH_MAX; #else static int pathmax = 0; #endif #define SUSV3 200112L static long posix_version = 0; /* If PATH_MAX is indeterminate, no guarantee t
#include "apue.h"
#include <errno.h>
#include <limits.h>
#ifdef PATH_MAX
static int pathmax = PATH_MAX;
#else
static int pathmax = 0;
#endif
#define SUSV3 200112L
static long posix_version = 0;
/* If PATH_MAX is indeterminate, no guarantee this is adequate */
#define PATH_MAX_GUESS 1024
char *
path_alloc(int *sizep) /* also return allocated size, if nonnull */
{
char *ptr;
int size;
if (posix_version == 0)
posix_version = sysconf(_SC_VERSION);
if (pathmax == 0) { /* first time through */
errno = 0; /* From: http://www.bianceng.cn */
if ((pathmax = pathconf("/", _PC_PATH_MAX)) < 0) {
if (errno == 0)
pathmax = PATH_MAX_GUESS; /* it's indeterminate */
else
err_sys("pathconf error for _PC_PATH_MAX");
} else {
pathmax++; /* add one since it's relative to root */
}
}
if (posix_version < SUSV3)
size = pathmax + 1;
else
size = pathmax;
if ((ptr = malloc(size)) == NULL)
err_sys("malloc error for pathname");
if (sizep != NULL)
*sizep = size;
return(ptr);
}
或
char*path_alloc(int* size)
{
char *p = NULL;
if(!size) return NULL;
p = malloc(256);
if(p)
*size = 256;
else
*size = 0;
return p;
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