Mysql中按月和日为组group并进行统计排序order - MySQL教程
在数据库中我们经常用sql语句对表进行简单的统计排序,对于日期字段,我们可以简单的对其进行order。对于复杂一点的可以按日期中的年,月,日分别进行group,order。
按年份进行group,统计排序: SELECT YERA(established_time) ,COUNT(*) AS num <span style="font-size: 13.75px; font-family: Arial, Helvetica, sans-serif;">FROM `table_record` GROUP BY YEAR (established_time)</span> 按月份进行group,统计排序: 方法一:简单实用 SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `table_record` GROUP BY YEAR (established_time) DESC, MONTH(established_time) 效果: year month count ------ ------ ------- 2014 1 8320 2014 2 5837 2014 3 25069 2014 4 29820 2014 5 25060 2014 6 17615 2014 7 1 2013 1 9114 2013 2 4258 方法二:利用 MySql内置字符串连接函数 CONCAT(str1, str2, ...,str3) 。 SELECT CONCAT(YEAR(established_time),',',MONTH( established_time)) AS data_time ,COUNT(*) AS num FROM `table_record` #group by data_time GROUP BY YEAR(established_time) DESC,MONTH( established_time) 本栏目更多精彩内容:http://www.bianceng.cn/database/MySQL/ 效果: data_time num --------- -------- 2014,1 8320 2014,2 5837 2014,3 25069 2014,4 29910 2014,5 25018 2014,6 17347 2014,7 1 2013,1 9114 2013,2 4258 2013,3 8047 注意这里不要用: SELECT YEAR(established_time)+MONTH( established_time) as data_time 这是错误的,它会造成2010+1=2011的这样的错误。 此外,若仅仅用下面语句,是统计的是多年来每月的数据。 SELECT MONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `tb_gongshangju_record_beijing` GROUP BY MONTH(established_time) DESC 效果如下: month count ------ -------- 12 44952 11 49720 10 38587 9 48967 8 52874 7 54082 6 69532 5 76999 4 87289 3 85249 2 39997 1 49017 (NULL) 34456 按日期day进行group,统计排序 SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' ,DAY(established_time) AS 'day', COUNT(*) AS 'count' FROM `table_record` WHERE table_record.`established_time` >= '2014-01-01' GROUP BY YEAR (established_time) DESC, MONTH(established_time) DESC ,DAY(established_time) DESC (编辑:佛山站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |